解释出门右转 线段树博文 谢谢

附:Add函数里面加 v 是因为我们最小值统计的只是一个元素。

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struct Node {
int L, R;
ll num, lazy;
Node() {}
Node(int L, int R, ll num) : L(L), R(R), num(num) {}
Node operator + (Node &you) const {
return Node(min(L, you.L), max(R, you.R), min(num, you.num));
}
};
class SegTree {
private :
Node node[N << 2];
public :
void Add(int p, ll v) {
node[p].lazy += v;
node[p].num += v;
}
void Pushdown(int p) {
if(node[p].lazy == 0) return ;
Add(p << 1, node[p].lazy);
Add(p << 1 | 1, node[p].lazy);
node[p].lazy = 0;
}
void Build(int p, int L, int R, int *a) {
node[p].L = L, node[p].R = R, node[p].lazy = 0;
if(L == R) {
node[p].num = a[L];
return ;
}
int mid = L + R >> 1;
Build(p << 1, L, mid, a);
Build(p << 1 | 1, mid + 1, R, a);
node[p] = node[p << 1] + node[p << 1 | 1];
}
void ModifyRange(int p, int L, int R, ll v) {
if(L <= node[p].L && node[p].R <= R) {
Add(p, v);
return ;
}
Pushdown(p);
int mid = node[p].L + node[p].R >> 1;
if(L <= mid) ModifyRange(p << 1, L, R, v);
if(mid < R) ModifyRange(p << 1 | 1, L, R, v);
node[p] = node[p << 1] + node[p << 1 | 1];
}
long long QueryRange(int p, int L, int R) {
if(L <= node[p].L && node[p].R <= R) {
return node[p].num;
}
Pushdown(p);
int mid = node[p].L + node[p].R >> 1;
long long ans = 1e18;
if(L <= mid) ans = min(ans, QueryRange(p << 1, L, R));
if(mid < R) ans = min(ans, QueryRange(p << 1 | 1, L, R));
return ans;
}
};